Evaluate square root of 1^2+2^2+3^2

$\sqrt{1^{2} + 2^{2} + 3^{2}}$

One to any power is one.

$\sqrt{1 + 2^{2} + 3^{2}}$

Raise $2$ to the power of $2$ .

$\sqrt{1 + 4 + 3^{2}}$

Raise $3$ to the power of $2$ .

$\sqrt{1 + 4 + 9}$

Add $1$ and $4$ .

$\sqrt{5 + 9}$

Add $5$ and $9$ .

$\sqrt{14}$

The result can be shown in multiple forms.

Exact Form:

$\sqrt{14}$

Decimal Form:

$3.74165738 \dots$

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