Evaluate square root of -1/2

$\sqrt{- \frac{1}{2}}$

Step 1

Rewrite $- \frac{1}{2}$ as $i^{2} \frac{1^{2}}{2}$ .

Rewrite $- 1$ as $i^{2}$ .

$\sqrt{i^{2} \frac{1}{2}}$

Rewrite $1$ as $1^{2}$ .

$\sqrt{i^{2} \frac{1^{2}}{2}}$

Step 2

Pull terms out from under the radical.

$i \sqrt{\frac{1^{2}}{2}}$

Step 3

One to any power is one.

$i \sqrt{\frac{1}{2}}$

Step 4

Rewrite $\sqrt{\frac{1}{2}}$ as $\frac{\sqrt{1}}{\sqrt{2}}$ .

$i \frac{\sqrt{1}}{\sqrt{2}}$

Step 5

Any root of $1$ is $1$ .

$i \frac{1}{\sqrt{2}}$

Step 6

Multiply $\frac{1}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$i (\frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}})$

Step 7

Combine and simplify the denominator.

Multiply $\frac{1}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$i \frac{\sqrt{2}}{\sqrt{2} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$i \frac{\sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$i \frac{\sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$i \frac{\sqrt{2}}{{\sqrt{2}}^{1 + 1}}$

Add $1$ and $1$ .

$i \frac{\sqrt{2}}{{\sqrt{2}}^{2}}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$i \frac{\sqrt{2}}{{(2^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$i \frac{\sqrt{2}}{2^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$i \frac{\sqrt{2}}{2^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$i \frac{\sqrt{2}}{2^{\frac{2}{2}}}$

Rewrite the expression.

$i \frac{\sqrt{2}}{2^{1}}$

Evaluate the exponent.

$i \frac{\sqrt{2}}{2}$

Step 8

Combine $i$ and $\frac{\sqrt{2}}{2}$ .

$\frac{i \sqrt{2}}{2}$

Evaluate square root of -1/2

Related Questions

Support LCMGCF.com by disabling your adblocker.