Evaluate square root of 11*2-6+5(4^2-9)

$\sqrt{11 \cdot 2 - 6} + 5 (4^{2} - 9)$

Simplify each term.

Multiply $11$ by $2$ .

$\sqrt{22 - 6} + 5 (4^{2} - 9)$

Subtract $6$ from $22$ .

$\sqrt{16} + 5 (4^{2} - 9)$

Rewrite $16$ as $4^{2}$ .

$\sqrt{4^{2}} + 5 (4^{2} - 9)$

Pull terms out from under the radical, assuming positive real numbers.

$4 + 5 (4^{2} - 9)$

Raise $4$ to the power of $2$ .

$4 + 5 (16 - 9)$

Subtract $9$ from $16$ .

$4 + 5 \cdot 7$

Multiply $5$ by $7$ .

$4 + 35$

Add $4$ and $35$ .

$39$