Evaluate square root of 12* square root of 3

$\sqrt{12} \cdot \sqrt{3}$

Step 1

Combine using the product rule for radicals.

$\sqrt{12 \cdot 3}$

Step 2

Write the expression using exponents.

Multiply $12$ by $3$ .

$\sqrt{36}$

Rewrite $36$ as $6^{2}$ .

$\sqrt{6^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$6$