Evaluate - square root of 16/49

$- \sqrt{\frac{16}{49}}$

Step 1

Rewrite $\sqrt{\frac{16}{49}}$ as $\frac{\sqrt{16}}{\sqrt{49}}$ .

$- \frac{\sqrt{16}}{\sqrt{49}}$

Step 2

Simplify the numerator.

Rewrite $16$ as $4^{2}$ .

$- \frac{\sqrt{4^{2}}}{\sqrt{49}}$

Pull terms out from under the radical, assuming positive real numbers.

$- \frac{4}{\sqrt{49}}$

Step 3

Simplify the denominator.

Rewrite $49$ as $7^{2}$ .

$- \frac{4}{\sqrt{7^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$- \frac{4}{7}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$- \frac{4}{7}$

Decimal Form:

$- 0.\overline{571428}$