Evaluate - square root of 16/9

$- \sqrt{\frac{16}{9}}$

Step 1

Rewrite $\sqrt{\frac{16}{9}}$ as $\frac{\sqrt{16}}{\sqrt{9}}$ .

$- \frac{\sqrt{16}}{\sqrt{9}}$

Step 2

Simplify the numerator.

Rewrite $16$ as $4^{2}$ .

$- \frac{\sqrt{4^{2}}}{\sqrt{9}}$

Pull terms out from under the radical, assuming positive real numbers.

$- \frac{4}{\sqrt{9}}$

Step 3

Simplify the denominator.

Rewrite $9$ as $3^{2}$ .

$- \frac{4}{\sqrt{3^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$- \frac{4}{3}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$- \frac{4}{3}$

Decimal Form:

$- 1.\overline{3}$

Mixed Number Form:

$- 1 \frac{1}{3}$