Evaluate square root of 16* square root of -1

$\sqrt{16} \cdot \sqrt{- 1}$

Step 1

Rewrite $\sqrt{- 1}$ as $i$ .

$\sqrt{16} \cdot i$

Step 2

Rewrite $16$ as $4^{2}$ .

$\sqrt{4^{2}} \cdot i$

Step 3

Pull terms out from under the radical, assuming positive real numbers.

$4 i$