Evaluate square root of 2* square root of 6

$\sqrt{2} \cdot \sqrt{6}$

Step 1

Combine using the product rule for radicals.

$\sqrt{2 \cdot 6}$

Step 2

Multiply $2$ by $6$ .

$\sqrt{12}$

Step 3

Rewrite $12$ as $2^{2} \cdot 3$ .

Factor $4$ out of $12$ .

$\sqrt{4 (3)}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 3}$

$\sqrt{2^{2} \cdot 3}$

Step 4

Pull terms out from under the radical.

$2 \sqrt{3}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$2 \sqrt{3}$

Decimal Form:

$3.46410161 \dots$

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