Evaluate - square root of 25/36

$- \sqrt{\frac{25}{36}}$

Step 1

Rewrite $\sqrt{\frac{25}{36}}$ as $\frac{\sqrt{25}}{\sqrt{36}}$ .

$- \frac{\sqrt{25}}{\sqrt{36}}$

Step 2

Simplify the numerator.

Rewrite $25$ as $5^{2}$ .

$- \frac{\sqrt{5^{2}}}{\sqrt{36}}$

Pull terms out from under the radical, assuming positive real numbers.

$- \frac{5}{\sqrt{36}}$

Step 3

Simplify the denominator.

Rewrite $36$ as $6^{2}$ .

$- \frac{5}{\sqrt{6^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$- \frac{5}{6}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$- \frac{5}{6}$

Decimal Form:

$- 0.8\overline{3}$