Evaluate square root of 3+ square root of 36

$\sqrt{3 + \sqrt{36}}$

Step 1

Rewrite $36$ as $6^{2}$ .

$\sqrt{3 + \sqrt{6^{2}}}$

Step 2

Pull terms out from under the radical, assuming positive real numbers.

$\sqrt{3 + 6}$

Step 3

Add $3$ and $6$ .

$\sqrt{9}$

Step 4

Rewrite $9$ as $3^{2}$ .

$\sqrt{3^{2}}$

Step 5

Pull terms out from under the radical, assuming positive real numbers.

$3$