Evaluate square root of 6(7- square root of 6)

$\sqrt{6} (7 - \sqrt{6})$

Step 1

Apply the distributive property.

$\sqrt{6} \cdot 7 + \sqrt{6} (- \sqrt{6})$

Step 2

Move $7$ to the left of $\sqrt{6}$ .

$7 \cdot \sqrt{6} + \sqrt{6} (- \sqrt{6})$

Step 3

Multiply $\sqrt{6} (- \sqrt{6})$ .

Raise $\sqrt{6}$ to the power of $1$ .

$7 \cdot \sqrt{6} - ({\sqrt{6}}^{1} \sqrt{6})$

Raise $\sqrt{6}$ to the power of $1$ .

$7 \cdot \sqrt{6} - ({\sqrt{6}}^{1} {\sqrt{6}}^{1})$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$7 \cdot \sqrt{6} - {\sqrt{6}}^{1 + 1}$

Add $1$ and $1$ .

$7 \cdot \sqrt{6} - {\sqrt{6}}^{2}$

Step 4

Simplify each term.

Rewrite ${\sqrt{6}}^{2}$ as $6$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{6}$ as $6^{\frac{1}{2}}$ .

$7 \sqrt{6} - {(6^{\frac{1}{2}})}^{2}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$7 \sqrt{6} - 6^{\frac{1}{2} \cdot 2}$

Combine $\frac{1}{2}$ and $2$ .

$7 \sqrt{6} - 6^{\frac{2}{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$7 \sqrt{6} - 6^{\frac{2}{2}}$

Rewrite the expression.

$7 \sqrt{6} - 6^{1}$

Evaluate the exponent.

$7 \sqrt{6} - 1 \cdot 6$

Multiply $- 1$ by $6$ .

$7 \sqrt{6} - 6$

Step 5

The result can be shown in multiple forms.

Exact Form:

$7 \sqrt{6} - 6$

Decimal Form:

$11.14642819 \dots$