Evaluate square root of -9/16

$\sqrt{- \frac{9}{16}}$

Step 1

Rewrite $- \frac{9}{16}$ as ${(\frac{3 i}{4})}^{2}$ .

$\sqrt{{(\frac{3 i}{4})}^{2}}$

Step 2

Pull terms out from under the radical, assuming positive real numbers.

$\frac{3 i}{4}$

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