Evaluate ( square root of 98)/(2^(1/2))

$\frac{\sqrt{98}}{2^{\frac{1}{2}}}$

Rewrite $98$ as $7^{2} \cdot 2$ .

Factor $49$ out of $98$ .

$\frac{\sqrt{49 (2)}}{2^{\frac{1}{2}}}$

Rewrite $49$ as $7^{2}$ .

$\frac{\sqrt{7^{2} \cdot 2}}{2^{\frac{1}{2}}}$

$\frac{\sqrt{7^{2} \cdot 2}}{2^{\frac{1}{2}}}$

Pull terms out from under the radical.

$\frac{7 \sqrt{2}}{2^{\frac{1}{2}}}$

The result can be shown in multiple forms.

Exact Form:

$\frac{7 \sqrt{2}}{2^{\frac{1}{2}}}$

Decimal Form:

$7$

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