Evaluate square root of (x-2)^2-8(x-2)

$\sqrt{{(x - 2)}^{2} - 8 (x - 2)}$

Step 1

Factor $x - 2$ out of ${(x - 2)}^{2} - 8 (x - 2)$ .

Factor $x - 2$ out of ${(x - 2)}^{2}$ .

$\sqrt{(x - 2) (x - 2) - 8 (x - 2)}$

Factor $x - 2$ out of $- 8 (x - 2)$ .

$\sqrt{(x - 2) (x - 2) + (x - 2) \cdot - 8}$

Factor $x - 2$ out of $(x - 2) (x - 2) + (x - 2) \cdot - 8$ .

$\sqrt{(x - 2) (x - 2 - 8)}$

Step 2

Subtract $8$ from $- 2$ .

$\sqrt{(x - 2) (x - 10)}$