Evaluate ( square root of x+2)^2

${(\sqrt{x} + 2)}^{2}$

Step 1

Rewrite ${(\sqrt{x} + 2)}^{2}$ as $(\sqrt{x} + 2) (\sqrt{x} + 2)$ .

$(\sqrt{x} + 2) (\sqrt{x} + 2)$

Step 2

Expand $(\sqrt{x} + 2) (\sqrt{x} + 2)$ using the FOIL Method.

Apply the distributive property.

$\sqrt{x} (\sqrt{x} + 2) + 2 (\sqrt{x} + 2)$

Apply the distributive property.

$\sqrt{x} \sqrt{x} + \sqrt{x} \cdot 2 + 2 (\sqrt{x} + 2)$

Apply the distributive property.

$\sqrt{x} \sqrt{x} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Step 3

Simplify and combine like terms.

Simplify each term.

Multiply $\sqrt{x} \sqrt{x}$ .

Raise $\sqrt{x}$ to the power of $1$ .

${\sqrt{x}}^{1} \sqrt{x} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Raise $\sqrt{x}$ to the power of $1$ .

${\sqrt{x}}^{1} {\sqrt{x}}^{1} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

${\sqrt{x}}^{1 + 1} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Add $1$ and $1$ .

${\sqrt{x}}^{2} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Rewrite ${\sqrt{x}}^{2}$ as $x$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

${(x^{\frac{1}{2}})}^{2} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Combine $\frac{1}{2}$ and $2$ .

$x^{\frac{2}{2}} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{2}{2}} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Rewrite the expression.

$x^{1} + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Simplify.

$x + \sqrt{x} \cdot 2 + 2 \sqrt{x} + 2 \cdot 2$

Move $2$ to the left of $\sqrt{x}$ .

$x + 2 \cdot \sqrt{x} + 2 \sqrt{x} + 2 \cdot 2$

Multiply $2$ by $2$ .

$x + 2 \sqrt{x} + 2 \sqrt{x} + 4$

Add $2 \sqrt{x}$ and $2 \sqrt{x}$ .

$x + 4 \sqrt{x} + 4$