Evaluate the Function f(-3)=x^4+4x^3+5x^2-3x+7

$f (- 3) = x^{4} + 4 x^{3} + 5 x^{2} - 3 x + 7$

Step 1

Replace the variable $x$ with $- 3$ in the expression.

$f (- 3) = {(- 3)}^{4} + 4 {(- 3)}^{3} + 5 {(- 3)}^{2} - 3 \cdot - 3 + 7$

Step 2

Simplify the result.

Simplify each term.

Raise $- 3$ to the power of $4$ .

$f (- 3) = 81 + 4 {(- 3)}^{3} + 5 {(- 3)}^{2} - 3 \cdot - 3 + 7$

Raise $- 3$ to the power of $3$ .

$f (- 3) = 81 + 4 \cdot - 27 + 5 {(- 3)}^{2} - 3 \cdot - 3 + 7$

Multiply $4$ by $- 27$ .

$f (- 3) = 81 - 108 + 5 {(- 3)}^{2} - 3 \cdot - 3 + 7$

Raise $- 3$ to the power of $2$ .

$f (- 3) = 81 - 108 + 5 \cdot 9 - 3 \cdot - 3 + 7$

Multiply $5$ by $9$ .

$f (- 3) = 81 - 108 + 45 - 3 \cdot - 3 + 7$

Multiply $- 3$ by $- 3$ .

$f (- 3) = 81 - 108 + 45 + 9 + 7$

Simplify by adding and subtracting.

Subtract $108$ from $81$ .

$f (- 3) = - 27 + 45 + 9 + 7$

Add $- 27$ and $45$ .

$f (- 3) = 18 + 9 + 7$

Add $18$ and $9$ .

$f (- 3) = 27 + 7$

Add $27$ and $7$ .

$f (- 3) = 34$

The final answer is $34$ .

$34$

Step 3