Evaluate the Function f(6)=2x^2+5 square root of x-2

$f (6) = 2 x^{2} + 5 \sqrt{x - 2}$

Step 1

Replace the variable $x$ with $6$ in the expression.

$f (6) = 2 {(6)}^{2} + 5 \sqrt{(6) - 2}$

Step 2

Simplify the result.

Simplify each term.

Raise $6$ to the power of $2$ .

$f (6) = 2 \cdot 36 + 5 \sqrt{(6) - 2}$

Multiply $2$ by $36$ .

$f (6) = 72 + 5 \sqrt{(6) - 2}$

Subtract $2$ from $6$ .

$f (6) = 72 + 5 \sqrt{4}$

Rewrite $4$ as $2^{2}$ .

$f (6) = 72 + 5 \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$f (6) = 72 + 5 \cdot 2$

Multiply $5$ by $2$ .

$f (6) = 72 + 10$

Add $72$ and $10$ .

$f (6) = 82$

The final answer is $82$ .

$82$

Step 3