Evaluate the Function f(x)=-2x^4+x^3+5x^2-3x-7 , x=-1

$f (x) = - 2 x^{4} + x^{3} + 5 x^{2} - 3 x - 7$ , $x = - 1$

Step 1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - 2 {(- 1)}^{4} + {(- 1)}^{3} + 5 {(- 1)}^{2} - 3 \cdot - 1 - 7$

Step 2

Simplify the result.

Simplify each term.

Raise $- 1$ to the power of $4$ .

$f (- 1) = - 2 \cdot 1 + {(- 1)}^{3} + 5 {(- 1)}^{2} - 3 \cdot - 1 - 7$

Multiply $- 2$ by $1$ .

$f (- 1) = - 2 + {(- 1)}^{3} + 5 {(- 1)}^{2} - 3 \cdot - 1 - 7$

Raise $- 1$ to the power of $3$ .

$f (- 1) = - 2 - 1 + 5 {(- 1)}^{2} - 3 \cdot - 1 - 7$

Raise $- 1$ to the power of $2$ .

$f (- 1) = - 2 - 1 + 5 \cdot 1 - 3 \cdot - 1 - 7$

Multiply $5$ by $1$ .

$f (- 1) = - 2 - 1 + 5 - 3 \cdot - 1 - 7$

Multiply $- 3$ by $- 1$ .

$f (- 1) = - 2 - 1 + 5 + 3 - 7$

Simplify by adding and subtracting.

Subtract $1$ from $- 2$ .

$f (- 1) = - 3 + 5 + 3 - 7$

Add $- 3$ and $5$ .

$f (- 1) = 2 + 3 - 7$

Add $2$ and $3$ .

$f (- 1) = 5 - 7$

Subtract $7$ from $5$ .

$f (- 1) = - 2$

The final answer is $- 2$ .

$- 2$

Step 3