Evaluate the Function f(x)=3x^3-3x^2+x-3 at x=-1

$f (x) = 3 x^{3} - 3 x^{2} + x - 3$ at $x = - 1$

Step 1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = 3 {(- 1)}^{3} - 3 {(- 1)}^{2} - 1 - 3$

Step 2

Simplify the result.

Remove parentheses.

$f (- 1) = 3 {(- 1)}^{3} - 3 {(- 1)}^{2} - 1 - 3$

Simplify each term.

Raise $- 1$ to the power of $3$ .

$f (- 1) = 3 \cdot - 1 - 3 {(- 1)}^{2} - 1 - 3$

Multiply $3$ by $- 1$ .

$f (- 1) = - 3 - 3 {(- 1)}^{2} - 1 - 3$

Raise $- 1$ to the power of $2$ .

$f (- 1) = - 3 - 3 \cdot 1 - 1 - 3$

Multiply $- 3$ by $1$ .

$f (- 1) = - 3 - 3 - 1 - 3$

Simplify by subtracting numbers.

Subtract $3$ from $- 3$ .

$f (- 1) = - 6 - 1 - 3$

Subtract $1$ from $- 6$ .

$f (- 1) = - 7 - 3$

Subtract $3$ from $- 7$ .

$f (- 1) = - 10$

The final answer is $- 10$ .

$- 10$

Step 3