Evaluate the Function f(x)=x^2+4x+3 at x=-1

$f (x) = x^{2} + 4 x + 3$ at $x = - 1$

Step 1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = {(- 1)}^{2} + 4 (- 1) + 3$

Step 2

Simplify the result.

Simplify each term.

Raise $- 1$ to the power of $2$ .

$f (- 1) = 1 + 4 (- 1) + 3$

Multiply $4$ by $- 1$ .

$f (- 1) = 1 - 4 + 3$

Simplify by adding and subtracting.

Subtract $4$ from $1$ .

$f (- 1) = - 3 + 3$

Add $- 3$ and $3$ .

$f (- 1) = 0$

The final answer is $0$ .

$0$

Step 3