Evaluate the Function f(x)=-x^3-4x-2 at x=-1

$f (x) = - x^{3} - 4 x - 2$ at $x = - 1$

Step 1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - {(- 1)}^{3} - 4 \cdot - 1 - 2$

Step 2

Simplify the result.

Simplify each term.

Multiply $- 1$ by ${(- 1)}^{3}$ by adding the exponents.

Multiply $- 1$ by ${(- 1)}^{3}$ .

Raise $- 1$ to the power of $1$ .

$f (- 1) = (- 1) {(- 1)}^{3} - 4 \cdot - 1 - 2$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (- 1) = {(- 1)}^{1 + 3} - 4 \cdot - 1 - 2$

Add $1$ and $3$ .

$f (- 1) = {(- 1)}^{4} - 4 \cdot - 1 - 2$

Raise $- 1$ to the power of $4$ .

$f (- 1) = 1 - 4 \cdot - 1 - 2$

Multiply $- 4$ by $- 1$ .

$f (- 1) = 1 + 4 - 2$

Simplify by adding and subtracting.

Add $1$ and $4$ .

$f (- 1) = 5 - 2$

Subtract $2$ from $5$ .

$f (- 1) = 3$

The final answer is $3$ .

$3$

Step 3