Evaluate Using the Given Value f(11) = cube root of 11-3

$f (11) = \sqrt[3]{11 - 3}$

Step 1

Subtract $3$ from $11$ .

$f (11) = \sqrt[3]{8}$

Step 2

Rewrite $8$ as $2^{3}$ .

$f (11) = \sqrt[3]{2^{3}}$

Step 3

Pull terms out from under the radical, assuming real numbers.

$f (11) = 2$