Evaluate Using the Given Value f(-2)=(5/3)^-2

$f (- 2) = {(\frac{5}{3})}^{- 2}$

Step 1

Change the sign of the exponent by rewriting the base as its reciprocal.

$f (- 2) = {(\frac{3}{5})}^{2}$

Step 2

Apply the product rule to $\frac{3}{5}$ .

$f (- 2) = \frac{3^{2}}{5^{2}}$

Step 3

Raise $3$ to the power of $2$ .

$f (- 2) = \frac{9}{5^{2}}$

Step 4

Raise $5$ to the power of $2$ .

$f (- 2) = \frac{9}{25}$