Evaluate Using the Given Value f(65) = cube root of 65-1

$f (65) = \sqrt[3]{65 - 1}$

Step 1

Subtract $1$ from $65$ .

$f (65) = \sqrt[3]{64}$

Step 2

Rewrite $64$ as $4^{3}$ .

$f (65) = \sqrt[3]{4^{3}}$

Step 3

Pull terms out from under the radical, assuming real numbers.

$f (65) = 4$