Evaluate Using the Given Value (x+5)^6 , n=7

${(x + 5)}^{6}$ , $n = 7$

Step 1

Replace the variable $n$ with $7$ in the expression.

${(x + 5)}^{6}$

Step 2

Use the Binomial Theorem.

$x^{6} + 6 x^{5} \cdot 5 + 15 x^{4} \cdot 5^{2} + 20 x^{3} \cdot 5^{3} + 15 x^{2} \cdot 5^{4} + 6 x \cdot 5^{5} + 5^{6}$

Step 3

Simplify each term.

Multiply $5$ by $6$ .

$x^{6} + 30 x^{5} + 15 x^{4} \cdot 5^{2} + 20 x^{3} \cdot 5^{3} + 15 x^{2} \cdot 5^{4} + 6 x \cdot 5^{5} + 5^{6}$

Raise $5$ to the power of $2$ .

$x^{6} + 30 x^{5} + 15 x^{4} \cdot 25 + 20 x^{3} \cdot 5^{3} + 15 x^{2} \cdot 5^{4} + 6 x \cdot 5^{5} + 5^{6}$

Multiply $25$ by $15$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 20 x^{3} \cdot 5^{3} + 15 x^{2} \cdot 5^{4} + 6 x \cdot 5^{5} + 5^{6}$

Raise $5$ to the power of $3$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 20 x^{3} \cdot 125 + 15 x^{2} \cdot 5^{4} + 6 x \cdot 5^{5} + 5^{6}$

Multiply $125$ by $20$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 2500 x^{3} + 15 x^{2} \cdot 5^{4} + 6 x \cdot 5^{5} + 5^{6}$

Raise $5$ to the power of $4$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 2500 x^{3} + 15 x^{2} \cdot 625 + 6 x \cdot 5^{5} + 5^{6}$

Multiply $625$ by $15$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 2500 x^{3} + 9375 x^{2} + 6 x \cdot 5^{5} + 5^{6}$

Raise $5$ to the power of $5$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 2500 x^{3} + 9375 x^{2} + 6 x \cdot 3125 + 5^{6}$

Multiply $3125$ by $6$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 2500 x^{3} + 9375 x^{2} + 18750 x + 5^{6}$

Raise $5$ to the power of $6$ .

$x^{6} + 30 x^{5} + 375 x^{4} + 2500 x^{3} + 9375 x^{2} + 18750 x + 15625$