Evaluate x/(2a)=-b plus or minus square root of b^2-4ac

$\frac{x}{2 a} = - b \pm \sqrt{b^{2} - 4 a c}$

Multiply both sides by $2 a$ .

$\frac{x}{2 a} (2 a) = (- b \pm \sqrt{b^{2} - 4 a c}) (2 a)$

Simplify.

Simplify the left side.

Simplify $\frac{x}{2 a} (2 a)$ .

Rewrite using the commutative property of multiplication.

$2 \frac{x}{2 a} a = (- b \pm \sqrt{b^{2} - 4 a c}) (2 a)$

Cancel the common factor of $2$ .

Factor $2$ out of $2 a$ .

$2 \frac{x}{2 (a)} a = (- b \pm \sqrt{b^{2} - 4 a c}) (2 a)$

Cancel the common factor.

$2 \frac{x}{2 a} a = (- b \pm \sqrt{b^{2} - 4 a c}) (2 a)$

Rewrite the expression.

$\frac{x}{a} a = (- b \pm \sqrt{b^{2} - 4 a c}) (2 a)$

Cancel the common factor of $a$ .

Cancel the common factor.

$\frac{x}{a} a = (- b \pm \sqrt{b^{2} - 4 a c}) (2 a)$

Rewrite the expression.

$x = (- b \pm \sqrt{b^{2} - 4 a c}) (2 a)$

Simplify the right side.

Rewrite using the commutative property of multiplication.

$x = 2 (- b \pm \sqrt{b^{2} - 4 a c}) a$