Evaluate x-(2x+1)=8-(3x+3)

$x - (2 x + 1) = 8 - (3 x + 3)$

Step 1

Simplify $x - (2 x + 1)$ .

Simplify each term.

Apply the distributive property.

$x - (2 x) - 1 \cdot 1 = 8 - (3 x + 3)$

Multiply $2$ by $- 1$ .

$x - 2 x - 1 \cdot 1 = 8 - (3 x + 3)$

Multiply $- 1$ by $1$ .

$x - 2 x - 1 = 8 - (3 x + 3)$

Subtract $2 x$ from $x$ .

$- x - 1 = 8 - (3 x + 3)$

Step 2

Simplify $8 - (3 x + 3)$ .

Simplify each term.

Apply the distributive property.

$- x - 1 = 8 - (3 x) - 1 \cdot 3$

Multiply $3$ by $- 1$ .

$- x - 1 = 8 - 3 x - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$- x - 1 = 8 - 3 x - 3$

Subtract $3$ from $8$ .

$- x - 1 = - 3 x + 5$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$- x - 1 + 3 x = 5$

Add $- x$ and $3 x$ .

$2 x - 1 = 5$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $1$ to both sides of the equation.

$2 x = 5 + 1$

Add $5$ and $1$ .

$2 x = 6$

Step 5

Divide each term in $2 x = 6$ by $2$ and simplify.

Divide each term in $2 x = 6$ by $2$ .

$\frac{2 x}{2} = \frac{6}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{6}{2}$

Divide $x$ by $1$ .

$x = \frac{6}{2}$

Simplify the right side.

Divide $6$ by $2$ .

$x = 3$

Evaluate x-(2x+1)=8-(3x+3)

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