Evaluate (x+3)^2=7

${(x + 3)}^{2} = 7$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x + 3 = \pm \sqrt{7}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x + 3 = \sqrt{7}$

Subtract $3$ from both sides of the equation.

$x = \sqrt{7} - 3$

Next, use the negative value of the $\pm$ to find the second solution.

$x + 3 = - \sqrt{7}$

Subtract $3$ from both sides of the equation.

$x = - \sqrt{7} - 3$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt{7} - 3, - \sqrt{7} - 3$

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt{7} - 3, - \sqrt{7} - 3$

Decimal Form:

$x = - 0.35424868 \dots, - 5.64575131 \dots$