Evaluate |x-5|>14

$| x - 5 | > 14$

Step 1

Write $| x - 5 | > 14$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$x - 5 \geq 0$

Add $5$ to both sides of the inequality.

$x \geq 5$

In the piece where $x - 5$ is non-negative, remove the absolute value.

$x - 5 > 14$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$x - 5 < 0$

Add $5$ to both sides of the inequality.

$x < 5$

In the piece where $x - 5$ is negative, remove the absolute value and multiply by $- 1$ .

$- (x - 5) > 14$

Write as a piecewise.

${\begin{cases} x - 5 > 14 & x \geq 5 \\ - (x - 5) > 14 & x < 5 \end{cases}$

Simplify $- (x - 5) > 14$ .

Apply the distributive property.

${\begin{cases} x - 5 > 14 & x \geq 5 \\ - x - - 5 > 14 & x < 5 \end{cases}$

Multiply $- 1$ by $- 5$ .

${\begin{cases} x - 5 > 14 & x \geq 5 \\ - x + 5 > 14 & x < 5 \end{cases}$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $5$ to both sides of the inequality.

$x > 14 + 5$

Add $14$ and $5$ .

$x > 19$

Step 3

Solve $- x + 5 > 14$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $5$ from both sides of the inequality.

$- x > 14 - 5$

Subtract $5$ from $14$ .

$- x > 9$

Divide each term in $- x > 9$ by $- 1$ and simplify.

Divide each term in $- x > 9$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} < \frac{9}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} < \frac{9}{- 1}$

Divide $x$ by $1$ .

$x < \frac{9}{- 1}$

Simplify the right side.

Divide $9$ by $- 1$ .

$x < - 9$

Step 4

Find the union of the solutions.

$x < - 9$ or $x > 19$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$x < - 9 or x > 19$

Interval Notation:

$(- \infty, - 9) \cup (19, \infty)$

Step 6

Evaluate |x-5|>14

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