Evaluate x=(-b+ square root of b^2-4ac)/(2a)

$x = \frac{- b + \sqrt{b^{2} - 4 a c}}{2 a}$

Step 1

Factor $- 1$ out of $- b$ .

$x = \frac{- (b) + \sqrt{b^{2} - 4 a c}}{2 a}$

Step 2

Factor $- 1$ out of $\sqrt{b^{2} - 4 a c}$ .

$x = \frac{- (b) - 1 (- \sqrt{b^{2} - 4 a c})}{2 a}$

Step 3

Factor $- 1$ out of $- (b) - 1 (- \sqrt{b^{2} - 4 a c})$ .

$x = \frac{- (b - \sqrt{b^{2} - 4 a c})}{2 a}$

Step 4

Simplify the expression.

Rewrite $- (b - \sqrt{b^{2} - 4 a c})$ as $- 1 (b - \sqrt{b^{2} - 4 a c})$ .

$x = \frac{- 1 (b - \sqrt{b^{2} - 4 a c})}{2 a}$

Move the negative in front of the fraction.

$x = - \frac{b - \sqrt{b^{2} - 4 a c}}{2 a}$