Expand the Logarithmic Expression log base 2 of 12

$\log_{2} (12)$

Rewrite $\log_{2} (12)$ as $\log_{2} (2^{2} \cdot 3)$ .

$\log_{2} (2^{2} \cdot 3)$

Rewrite $\log_{2} (2^{2} \cdot 3)$ as $\log_{2} (2^{2}) + \log_{2} (3)$ .

$\log_{2} (2^{2}) + \log_{2} (3)$

Use logarithm rules to move $2$ out of the exponent.

$2 \log_{2} (2) + \log_{2} (3)$

Logarithm base $2$ of $2$ is $1$ .

$2 \cdot 1 + \log_{2} (3)$

Multiply $2$ by $1$ .

$2 + \log_{2} (3)$