Expand the Logarithmic Expression log base 3 of 1/27

$\log_{3} (\frac{1}{27})$

Rewrite $\log_{3} (\frac{1}{27})$ as $\log_{3} (1) - \log_{3} (27)$ .

$\log_{3} (1) - \log_{3} (27)$

Logarithm base $3$ of $1$ is $0$ .

$0 - \log_{3} (27)$

Logarithm base $3$ of $27$ is $3$ .

$0 - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$0 - 3$

Subtract $3$ from $0$ .

$- 3$