Expand the Logarithmic Expression log base 3 of 9/y

$\log_{3} (\frac{9}{y})$

Step 1

Rewrite $\log_{3} (\frac{9}{y})$ as $\log_{3} (9) - \log_{3} (y)$ .

$\log_{3} (9) - \log_{3} (y)$

Step 2

Logarithm base $3$ of $9$ is $2$ .

$2 - \log_{3} (y)$