Expand the Logarithmic Expression log base 3 of c/9

$\log_{3} (\frac{c}{9})$

Rewrite $\log_{3} (\frac{c}{9})$ as $\log_{3} (c) - \log_{3} (9)$ .

$\log_{3} (c) - \log_{3} (9)$

Logarithm base $3$ of $9$ is $2$ .

$\log_{3} (c) - 1 \cdot 2$

Multiply $- 1$ by $2$ .

$\log_{3} (c) - 2$