Expand the Logarithmic Expression log base 5 of 1/125

$\log_{5} (\frac{1}{125})$

Rewrite $\log_{5} (\frac{1}{125})$ as $\log_{5} (1) - \log_{5} (125)$ .

$\log_{5} (1) - \log_{5} (125)$

Logarithm base $5$ of $1$ is $0$ .

$0 - \log_{5} (125)$

Logarithm base $5$ of $125$ is $3$ .

$0 - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$0 - 3$

Subtract $3$ from $0$ .

$- 3$