Expand the Logarithmic Expression log base 5 of 5^(x-5)

$\log_{5} (5^{x - 5})$

Expand $\log_{5} (5^{x - 5})$ by moving $x - 5$ outside the logarithm.

$(x - 5) \log_{5} (5)$

Logarithm base $5$ of $5$ is $1$ .

$(x - 5) \cdot 1$

Multiply $x - 5$ by $1$ .

$x - 5$