Expand the Logarithmic Expression log base 6 of 1296x

$\log_{6} (1296 x)$

Step 1

Rewrite $\log_{6} (1296 x)$ as $\log_{6} (1296) + \log_{6} (x)$ .

$\log_{6} (1296) + \log_{6} (x)$

Step 2

Logarithm base $6$ of $1296$ is $4$ .

$4 + \log_{6} (x)$