Expand the Logarithmic Expression log base 7 of 1/49

$\log_{7} (\frac{1}{49})$

Step 1

Rewrite $\log_{7} (\frac{1}{49})$ as $\log_{7} (1) - \log_{7} (49)$ .

$\log_{7} (1) - \log_{7} (49)$

Step 2

Logarithm base $7$ of $1$ is $0$ .

$0 - \log_{7} (49)$

Step 3

Logarithm base $7$ of $49$ is $2$ .

$0 - 1 \cdot 2$

Step 4

Multiply $- 1$ by $2$ .

$0 - 2$

Step 5

Subtract $2$ from $0$ .

$- 2$