Expand the Trigonometric Expression (2i^2+3a-5n)^2

${(2 i^{2} + 3 a - 5 n)}^{2}$

Step 1

Simplify terms.

Simplify each term.

Rewrite $i^{2}$ as $- 1$ .

${(2 \cdot - 1 + 3 a - 5 n)}^{2}$

Multiply $2$ by $- 1$ .

${(- 2 + 3 a - 5 n)}^{2}$

Rewrite ${(- 2 + 3 a - 5 n)}^{2}$ as $(- 2 + 3 a - 5 n) (- 2 + 3 a - 5 n)$ .

$(- 2 + 3 a - 5 n) (- 2 + 3 a - 5 n)$

Step 2

Expand $(- 2 + 3 a - 5 n) (- 2 + 3 a - 5 n)$ by multiplying each term in the first expression by each term in the second expression.

$- 2 \cdot - 2 - 2 (3 a) - 2 (- 5 n) + 3 a \cdot - 2 + 3 a (3 a) + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Step 3

Simplify terms.

Simplify each term.

Multiply $- 2$ by $- 2$ .

$4 - 2 (3 a) - 2 (- 5 n) + 3 a \cdot - 2 + 3 a (3 a) + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $3$ by $- 2$ .

$4 - 6 a - 2 (- 5 n) + 3 a \cdot - 2 + 3 a (3 a) + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $- 5$ by $- 2$ .

$4 - 6 a + 10 n + 3 a \cdot - 2 + 3 a (3 a) + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $- 2$ by $3$ .

$4 - 6 a + 10 n - 6 a + 3 a (3 a) + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Rewrite using the commutative property of multiplication.

$4 - 6 a + 10 n - 6 a + 3 \cdot 3 a \cdot a + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $a$ by $a$ by adding the exponents.

Move $a$ .

$4 - 6 a + 10 n - 6 a + 3 \cdot 3 (a \cdot a) + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $a$ by $a$ .

$4 - 6 a + 10 n - 6 a + 3 \cdot 3 a^{2} + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $3$ by $3$ .

$4 - 6 a + 10 n - 6 a + 9 a^{2} + 3 a (- 5 n) - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Rewrite using the commutative property of multiplication.

$4 - 6 a + 10 n - 6 a + 9 a^{2} + 3 \cdot - 5 a n - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $3$ by $- 5$ .

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n - 5 n \cdot - 2 - 5 n (3 a) - 5 n (- 5 n)$

Multiply $- 2$ by $- 5$ .

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n + 10 n - 5 n (3 a) - 5 n (- 5 n)$

Rewrite using the commutative property of multiplication.

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n + 10 n - 5 \cdot 3 n a - 5 n (- 5 n)$

Multiply $- 5$ by $3$ .

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n + 10 n - 15 n a - 5 n (- 5 n)$

Rewrite using the commutative property of multiplication.

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n + 10 n - 15 n a - 5 \cdot - 5 n \cdot n$

Multiply $n$ by $n$ by adding the exponents.

Move $n$ .

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n + 10 n - 15 n a - 5 \cdot - 5 (n \cdot n)$

Multiply $n$ by $n$ .

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n + 10 n - 15 n a - 5 \cdot - 5 n^{2}$

Multiply $- 5$ by $- 5$ .

$4 - 6 a + 10 n - 6 a + 9 a^{2} - 15 a n + 10 n - 15 n a + 25 n^{2}$

Simplify by adding terms.

Subtract $6 a$ from $- 6 a$ .

$4 - 12 a + 10 n + 9 a^{2} - 15 a n + 10 n - 15 n a + 25 n^{2}$

Add $10 n$ and $10 n$ .

$4 - 12 a + 9 a^{2} - 15 a n + 20 n - 15 n a + 25 n^{2}$

Step 4

Subtract $15 n a$ from $- 15 a n$ .

Move $n$ .

$4 - 12 a + 9 a^{2} - 15 a n - 15 a n + 20 n + 25 n^{2}$

Subtract $15 a n$ from $- 15 a n$ .

$4 - 12 a + 9 a^{2} - 30 a n + 20 n + 25 n^{2}$

Expand the Trigonometric Expression (2i^2+3a-5n)^2

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