Expand the Trigonometric Expression (4+h)^3

${(4 + h)}^{3}$

Step 1

Use the Binomial Theorem.

$4^{3} + 3 \cdot 4^{2} h + 3 \cdot 4 h^{2} + h^{3}$

Step 2

Simplify each term.

Raise $4$ to the power of $3$ .

$64 + 3 \cdot 4^{2} h + 3 \cdot 4 h^{2} + h^{3}$

Raise $4$ to the power of $2$ .

$64 + 3 \cdot 16 h + 3 \cdot 4 h^{2} + h^{3}$

Multiply $3$ by $16$ .

$64 + 48 h + 3 \cdot 4 h^{2} + h^{3}$

Multiply $3$ by $4$ .

$64 + 48 h + 12 h^{2} + h^{3}$