Expand Using Pascal's Triangle (2x+1/(x^3))^8

${(2 x + \frac{1}{x^{3}})}^{8}$

Step 1

Pascal\'s Triangle can be displayed as such:

$1$

$1 - 1$

$1 - 2 - 1$

$\dots$

$1 - 6 - 15 - 20 - 15 - 6 - 1$

$1 - 7 - 21 - 35 - 35 - 21 - 7 - 1$

$1 - 8 - 28 - 56 - 70 - 56 - 28 - 8 - 1$

The triangle can be used to calculate the coefficients of the expansion of ${(a + b)}^{n}$ by taking the exponent $n$ and adding $1$ . The coefficients will correspond with line $n + 1$ of the triangle. For ${(2 x + \frac{1}{x^{3}})}^{8}$ , $n = 8$ so the coefficients of the expansion will correspond with line $9$ .

Step 2

The expansion follows the rule ${(a + b)}^{n} = c_{0} a^{n} b^{0} + c_{1} a^{n - 1} b^{1} + c_{n - 1} a^{1} b^{n - 1} + c_{n} a^{0} b^{n}$ . The values of the coefficients, from the triangle, are $1 - 8 - 28 - 56 - 70 - 56 - 28 - 8 - 1$ .

$1 a^{8} b^{0} + 8 a^{7} b + 28 a^{6} b^{2} + 56 a^{5} b^{3} + 70 a^{4} b^{4} + 56 a^{3} b^{5} + 28 a^{2} b^{6} + 8 a b^{7} + 1 a^{0} b^{8}$

Step 3

Substitute the actual values of $a$ $2 x$ and $b$ $\frac{1}{x^{3}}$ into the expression.

$1 {(2 x)}^{8} {(\frac{1}{x^{3}})}^{0} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Step 4

Simplify each term.

Multiply ${(2 x)}^{8}$ by $1$ .

${(2 x)}^{8} {(\frac{1}{x^{3}})}^{0} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$2^{8} x^{8} {(\frac{1}{x^{3}})}^{0} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Raise $2$ to the power of $8$ .

$256 x^{8} {(\frac{1}{x^{3}})}^{0} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} \frac{1^{0}}{{(x^{3})}^{0}} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Anything raised to $0$ is $1$ .

$256 x^{8} \frac{1}{{(x^{3})}^{0}} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Simplify the denominator.

Multiply the exponents in ${(x^{3})}^{0}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} \frac{1}{x^{3 \cdot 0}} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $3$ by $0$ .

$256 x^{8} \frac{1}{x^{0}} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Anything raised to $0$ is $1$ .

$256 x^{8} \frac{1}{1} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Divide $1$ by $1$ .

$256 x^{8} \cdot 1 + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $256$ by $1$ .

$256 x^{8} + 8 {(2 x)}^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$256 x^{8} + 8 (2^{7} x^{7}) {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Raise $2$ to the power of $7$ .

$256 x^{8} + 8 (128 x^{7}) {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $128$ by $8$ .

$256 x^{8} + 1024 x^{7} {(\frac{1}{x^{3}})}^{1} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Simplify.

$256 x^{8} + 1024 x^{7} \frac{1}{x^{3}} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor of $x^{3}$ .

Factor $x^{3}$ out of $1024 x^{7}$ .

$256 x^{8} + x^{3} (1024 x^{4}) \frac{1}{x^{3}} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor.

Rewrite the expression.

$256 x^{8} + 1024 x^{4} + 28 {(2 x)}^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$256 x^{8} + 1024 x^{4} + 28 (2^{6} x^{6}) {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Raise $2$ to the power of $6$ .

$256 x^{8} + 1024 x^{4} + 28 (64 x^{6}) {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $64$ by $28$ .

$256 x^{8} + 1024 x^{4} + 1792 x^{6} {(\frac{1}{x^{3}})}^{2} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} + 1024 x^{4} + 1792 x^{6} \frac{1^{2}}{{(x^{3})}^{2}} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

One to any power is one.

$256 x^{8} + 1024 x^{4} + 1792 x^{6} \frac{1}{{(x^{3})}^{2}} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply the exponents in ${(x^{3})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} + 1024 x^{4} + 1792 x^{6} \frac{1}{x^{3 \cdot 2}} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $3$ by $2$ .

$256 x^{8} + 1024 x^{4} + 1792 x^{6} \frac{1}{x^{6}} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor of $x^{6}$ .

Factor $x^{6}$ out of $1792 x^{6}$ .

$256 x^{8} + 1024 x^{4} + x^{6} \cdot 1792 \frac{1}{x^{6}} + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor.

Rewrite the expression.

$256 x^{8} + 1024 x^{4} + 1792 + 56 {(2 x)}^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$256 x^{8} + 1024 x^{4} + 1792 + 56 (2^{5} x^{5}) {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Raise $2$ to the power of $5$ .

$256 x^{8} + 1024 x^{4} + 1792 + 56 (32 x^{5}) {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $32$ by $56$ .

$256 x^{8} + 1024 x^{4} + 1792 + 1792 x^{5} {(\frac{1}{x^{3}})}^{3} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + 1792 x^{5} \frac{1^{3}}{{(x^{3})}^{3}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

One to any power is one.

$256 x^{8} + 1024 x^{4} + 1792 + 1792 x^{5} \frac{1}{{(x^{3})}^{3}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply the exponents in ${(x^{3})}^{3}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} + 1024 x^{4} + 1792 + 1792 x^{5} \frac{1}{x^{3 \cdot 3}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $3$ by $3$ .

$256 x^{8} + 1024 x^{4} + 1792 + 1792 x^{5} \frac{1}{x^{9}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor of $x^{5}$ .

Factor $x^{5}$ out of $1792 x^{5}$ .

$256 x^{8} + 1024 x^{4} + 1792 + x^{5} \cdot 1792 \frac{1}{x^{9}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Factor $x^{5}$ out of $x^{9}$ .

$256 x^{8} + 1024 x^{4} + 1792 + x^{5} \cdot 1792 \frac{1}{x^{5} x^{4}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor.

Rewrite the expression.

$256 x^{8} + 1024 x^{4} + 1792 + 1792 \frac{1}{x^{4}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Combine $1792$ and $\frac{1}{x^{4}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 70 {(2 x)}^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 70 (2^{4} x^{4}) {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Raise $2$ to the power of $4$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 70 (16 x^{4}) {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $16$ by $70$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 1120 x^{4} {(\frac{1}{x^{3}})}^{4} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 1120 x^{4} \frac{1^{4}}{{(x^{3})}^{4}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

One to any power is one.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 1120 x^{4} \frac{1}{{(x^{3})}^{4}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply the exponents in ${(x^{3})}^{4}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 1120 x^{4} \frac{1}{x^{3 \cdot 4}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $3$ by $4$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 1120 x^{4} \frac{1}{x^{12}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor of $x^{4}$ .

Factor $x^{4}$ out of $1120 x^{4}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + x^{4} \cdot 1120 \frac{1}{x^{12}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Factor $x^{4}$ out of $x^{12}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + x^{4} \cdot 1120 \frac{1}{x^{4} x^{8}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor.

Rewrite the expression.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + 1120 \frac{1}{x^{8}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Combine $1120$ and $\frac{1}{x^{8}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 56 {(2 x)}^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 56 (2^{3} x^{3}) {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Raise $2$ to the power of $3$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 56 (8 x^{3}) {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $8$ by $56$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 448 x^{3} {(\frac{1}{x^{3}})}^{5} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 448 x^{3} \frac{1^{5}}{{(x^{3})}^{5}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

One to any power is one.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 448 x^{3} \frac{1}{{(x^{3})}^{5}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply the exponents in ${(x^{3})}^{5}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 448 x^{3} \frac{1}{x^{3 \cdot 5}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $3$ by $5$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 448 x^{3} \frac{1}{x^{15}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor of $x^{3}$ .

Factor $x^{3}$ out of $448 x^{3}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + x^{3} \cdot 448 \frac{1}{x^{15}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Factor $x^{3}$ out of $x^{15}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + x^{3} \cdot 448 \frac{1}{x^{3} x^{12}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor.

Rewrite the expression.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + 448 \frac{1}{x^{12}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Combine $448$ and $\frac{1}{x^{12}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 28 {(2 x)}^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 28 (2^{2} x^{2}) {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Raise $2$ to the power of $2$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 28 (4 x^{2}) {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $4$ by $28$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 112 x^{2} {(\frac{1}{x^{3}})}^{6} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 112 x^{2} \frac{1^{6}}{{(x^{3})}^{6}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

One to any power is one.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 112 x^{2} \frac{1}{{(x^{3})}^{6}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply the exponents in ${(x^{3})}^{6}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 112 x^{2} \frac{1}{x^{3 \cdot 6}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $3$ by $6$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 112 x^{2} \frac{1}{x^{18}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor of $x^{2}$ .

Factor $x^{2}$ out of $112 x^{2}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + x^{2} \cdot 112 \frac{1}{x^{18}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Factor $x^{2}$ out of $x^{18}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + x^{2} \cdot 112 \frac{1}{x^{2} x^{16}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor.

Rewrite the expression.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + 112 \frac{1}{x^{16}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Combine $112$ and $\frac{1}{x^{16}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 8 {(2 x)}^{1} {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Simplify.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 8 (2 x) {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $2$ by $8$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 16 x {(\frac{1}{x^{3}})}^{7} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 16 x \frac{1^{7}}{{(x^{3})}^{7}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

One to any power is one.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 16 x \frac{1}{{(x^{3})}^{7}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply the exponents in ${(x^{3})}^{7}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 16 x \frac{1}{x^{3 \cdot 7}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $3$ by $7$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 16 x \frac{1}{x^{21}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor of $x$ .

Factor $x$ out of $16 x$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + x \cdot 16 \frac{1}{x^{21}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Factor $x$ out of $x^{21}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + x \cdot 16 \frac{1}{x \cdot x^{20}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Cancel the common factor.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + x \cdot 16 \frac{1}{x \cdot x^{20}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Rewrite the expression.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + 16 \frac{1}{x^{20}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Combine $16$ and $\frac{1}{x^{20}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + 1 {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply ${(2 x)}^{0}$ by $1$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + {(2 x)}^{0} {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $2 x$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + 2^{0} x^{0} {(\frac{1}{x^{3}})}^{8}$

Anything raised to $0$ is $1$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + 1 x^{0} {(\frac{1}{x^{3}})}^{8}$

Multiply $x^{0}$ by $1$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + x^{0} {(\frac{1}{x^{3}})}^{8}$

Anything raised to $0$ is $1$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + 1 {(\frac{1}{x^{3}})}^{8}$

Multiply ${(\frac{1}{x^{3}})}^{8}$ by $1$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + {(\frac{1}{x^{3}})}^{8}$

Apply the product rule to $\frac{1}{x^{3}}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + \frac{1^{8}}{{(x^{3})}^{8}}$

One to any power is one.

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + \frac{1}{{(x^{3})}^{8}}$

Multiply the exponents in ${(x^{3})}^{8}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + \frac{1}{x^{3 \cdot 8}}$

Multiply $3$ by $8$ .

$256 x^{8} + 1024 x^{4} + 1792 + \frac{1792}{x^{4}} + \frac{1120}{x^{8}} + \frac{448}{x^{12}} + \frac{112}{x^{16}} + \frac{16}{x^{20}} + \frac{1}{x^{24}}$

Expand Using Pascal's Triangle (2x+1/(x^3))^8

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