Expand Using Pascal's Triangle (2x^3+1)^5

${(2 x^{3} + 1)}^{5}$

Step 1

Pascal\'s Triangle can be displayed as such:

$1$

$1 - 1$

$1 - 2 - 1$

$1 - 3 - 3 - 1$

$1 - 4 - 6 - 4 - 1$

$1 - 5 - 10 - 10 - 5 - 1$

The triangle can be used to calculate the coefficients of the expansion of ${(a + b)}^{n}$ by taking the exponent $n$ and adding $1$ . The coefficients will correspond with line $n + 1$ of the triangle. For ${(2 x^{3} + 1)}^{5}$ , $n = 5$ so the coefficients of the expansion will correspond with line $6$ .

Step 2

The expansion follows the rule ${(a + b)}^{n} = c_{0} a^{n} b^{0} + c_{1} a^{n - 1} b^{1} + c_{n - 1} a^{1} b^{n - 1} + c_{n} a^{0} b^{n}$ . The values of the coefficients, from the triangle, are $1 - 5 - 10 - 10 - 5 - 1$ .

$1 a^{5} b^{0} + 5 a^{4} b + 10 a^{3} b^{2} + 10 a^{2} b^{3} + 5 a b^{4} + 1 a^{0} b^{5}$

Step 3

Substitute the actual values of $a$ $2 x^{3}$ and $b$ $1$ into the expression.

$1 {(2 x^{3})}^{5} {(1)}^{0} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Step 4

Simplify each term.

Multiply $1$ by ${(1)}^{0}$ by adding the exponents.

Move ${(1)}^{0}$ .

${(1)}^{0} \cdot 1 {(2 x^{3})}^{5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply ${(1)}^{0}$ by $1$ .

Raise $1$ to the power of $1$ .

${(1)}^{0} \cdot 1^{1} {(2 x^{3})}^{5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$1^{0 + 1} {(2 x^{3})}^{5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Add $0$ and $1$ .

$1^{1} {(2 x^{3})}^{5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Simplify $1^{1} {(2 x^{3})}^{5}$ .

${(2 x^{3})}^{5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Apply the product rule to $2 x^{3}$ .

$2^{5} {(x^{3})}^{5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Raise $2$ to the power of $5$ .

$32 {(x^{3})}^{5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply the exponents in ${(x^{3})}^{5}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$32 x^{3 \cdot 5} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $3$ by $5$ .

$32 x^{15} + 5 {(2 x^{3})}^{4} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Apply the product rule to $2 x^{3}$ .

$32 x^{15} + 5 (2^{4} {(x^{3})}^{4}) {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Raise $2$ to the power of $4$ .

$32 x^{15} + 5 (16 {(x^{3})}^{4}) {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply the exponents in ${(x^{3})}^{4}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$32 x^{15} + 5 (16 x^{3 \cdot 4}) {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $3$ by $4$ .

$32 x^{15} + 5 (16 x^{12}) {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $16$ by $5$ .

$32 x^{15} + 80 x^{12} {(1)}^{1} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Evaluate the exponent.

$32 x^{15} + 80 x^{12} \cdot 1 + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $80$ by $1$ .

$32 x^{15} + 80 x^{12} + 10 {(2 x^{3})}^{3} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Apply the product rule to $2 x^{3}$ .

$32 x^{15} + 80 x^{12} + 10 (2^{3} {(x^{3})}^{3}) {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Raise $2$ to the power of $3$ .

$32 x^{15} + 80 x^{12} + 10 (8 {(x^{3})}^{3}) {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply the exponents in ${(x^{3})}^{3}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$32 x^{15} + 80 x^{12} + 10 (8 x^{3 \cdot 3}) {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $3$ by $3$ .

$32 x^{15} + 80 x^{12} + 10 (8 x^{9}) {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $8$ by $10$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} {(1)}^{2} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

One to any power is one.

$32 x^{15} + 80 x^{12} + 80 x^{9} \cdot 1 + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $80$ by $1$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 10 {(2 x^{3})}^{2} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Apply the product rule to $2 x^{3}$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 10 (2^{2} {(x^{3})}^{2}) {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Raise $2$ to the power of $2$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 10 (4 {(x^{3})}^{2}) {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply the exponents in ${(x^{3})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 10 (4 x^{3 \cdot 2}) {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $3$ by $2$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 10 (4 x^{6}) {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $4$ by $10$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} {(1)}^{3} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

One to any power is one.

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} \cdot 1 + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $40$ by $1$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 5 {(2 x^{3})}^{1} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Simplify.

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 5 (2 x^{3}) {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $2$ by $5$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} {(1)}^{4} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

One to any power is one.

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} \cdot 1 + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $10$ by $1$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} + 1 {(2 x^{3})}^{0} {(1)}^{5}$

Multiply $1$ by ${(1)}^{5}$ by adding the exponents.

Move ${(1)}^{5}$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} + {(1)}^{5} \cdot 1 {(2 x^{3})}^{0}$

Multiply ${(1)}^{5}$ by $1$ .

Raise $1$ to the power of $1$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} + {(1)}^{5} \cdot 1^{1} {(2 x^{3})}^{0}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} + 1^{5 + 1} {(2 x^{3})}^{0}$

Add $5$ and $1$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} + 1^{6} {(2 x^{3})}^{0}$

Simplify $1^{6} {(2 x^{3})}^{0}$ .

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} + 1^{6}$

One to any power is one.

$32 x^{15} + 80 x^{12} + 80 x^{9} + 40 x^{6} + 10 x^{3} + 1$

Expand Using Pascal's Triangle (2x^3+1)^5

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