Expand Using the Binomial Theorem (2x-3y)^6

${(2 x - 3 y)}^{6}$

Step 1

Use the binomial expansion theorem to find each term. The binomial theorem states ${(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})$ .

$\sum_{k = 0}^{6} \frac{6!}{(6 - k)! k!} \cdot {(2 x)}^{6 - k} \cdot {(- 3 y)}^{k}$

Step 2

Expand the summation.

$\frac{6!}{(6 - 0)! 0!} \cdot {(2 x)}^{6 - 0} \cdot {(- 3 y)}^{0} + \frac{6!}{(6 - 1)! 1!} \cdot {(2 x)}^{6 - 1} \cdot {(- 3 y)}^{1} + \dots + \frac{6!}{(6 - 6)! 6!} \cdot {(2 x)}^{6 - 6} \cdot {(- 3 y)}^{6}$

Step 3

Simplify the exponents for each term of the expansion.

$1 \cdot {(2 x)}^{6} \cdot {(- 3 y)}^{0} + 6 \cdot {(2 x)}^{5} \cdot {(- 3 y)}^{1} + \dots + 1 \cdot {(2 x)}^{0} \cdot {(- 3 y)}^{6}$

Step 4

Simplify the polynomial result.

$64 x^{6} - 576 x^{5} y + 2160 x^{4} y^{2} - 4320 x^{3} y^{3} + 4860 x^{2} y^{4} - 2916 x y^{5} + 729 y^{6}$

Expand Using the Binomial Theorem (2x-3y)^6

Related Questions

Support LCMGCF.com by disabling your adblocker.