Expand Using the Binomial Theorem (7m-8)^2

${(7 m - 8)}^{2}$

Step 1

Use the binomial expansion theorem to find each term. The binomial theorem states ${(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})$ .

$\sum_{k = 0}^{2} \frac{2!}{(2 - k)! k!} \cdot {(7 m)}^{2 - k} \cdot {(- 8)}^{k}$

Step 2

Expand the summation.

$\frac{2!}{(2 - 0)! 0!} \cdot {(7 m)}^{2 - 0} \cdot {(- 8)}^{0} + \frac{2!}{(2 - 1)! 1!} \cdot {(7 m)}^{2 - 1} \cdot {(- 8)}^{1} + \frac{2!}{(2 - 2)! 2!} \cdot {(7 m)}^{2 - 2} \cdot {(- 8)}^{2}$

Step 3

Simplify the exponents for each term of the expansion.

$1 \cdot {(7 m)}^{2} \cdot {(- 8)}^{0} + 2 \cdot {(7 m)}^{1} \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Step 4

Simplify each term.

Multiply ${(7 m)}^{2}$ by $1$ .

${(7 m)}^{2} \cdot {(- 8)}^{0} + 2 \cdot {(7 m)}^{1} \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Apply the product rule to $7 m$ .

$7^{2} m^{2} \cdot {(- 8)}^{0} + 2 \cdot {(7 m)}^{1} \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Raise $7$ to the power of $2$ .

$49 m^{2} \cdot {(- 8)}^{0} + 2 \cdot {(7 m)}^{1} \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Anything raised to $0$ is $1$ .

$49 m^{2} \cdot 1 + 2 \cdot {(7 m)}^{1} \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Multiply $49$ by $1$ .

$49 m^{2} + 2 \cdot {(7 m)}^{1} \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Simplify.

$49 m^{2} + 2 \cdot (7 m) \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Multiply $7$ by $2$ .

$49 m^{2} + 14 m \cdot {(- 8)}^{1} + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Evaluate the exponent.

$49 m^{2} + 14 m \cdot - 8 + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Multiply $- 8$ by $14$ .

$49 m^{2} - 112 m + 1 \cdot {(7 m)}^{0} \cdot {(- 8)}^{2}$

Multiply ${(7 m)}^{0}$ by $1$ .

$49 m^{2} - 112 m + {(7 m)}^{0} \cdot {(- 8)}^{2}$

Apply the product rule to $7 m$ .

$49 m^{2} - 112 m + 7^{0} m^{0} \cdot {(- 8)}^{2}$

Anything raised to $0$ is $1$ .

$49 m^{2} - 112 m + 1 m^{0} \cdot {(- 8)}^{2}$

Multiply $m^{0}$ by $1$ .

$49 m^{2} - 112 m + m^{0} \cdot {(- 8)}^{2}$

Anything raised to $0$ is $1$ .

$49 m^{2} - 112 m + 1 \cdot {(- 8)}^{2}$

Multiply ${(- 8)}^{2}$ by $1$ .

$49 m^{2} - 112 m + {(- 8)}^{2}$

Raise $- 8$ to the power of $2$ .

$49 m^{2} - 112 m + 64$

Expand Using the Binomial Theorem (7m-8)^2

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