Expand Using the Binomial Theorem (x+3)^7

${(x + 3)}^{7}$

Use the binomial expansion theorem to find each term. The binomial theorem states ${(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})$ .

$\sum_{k = 0}^{7} \frac{7!}{(7 - k)! k!} \cdot {(x)}^{7 - k} \cdot {(3)}^{k}$

Expand the summation.

$\frac{7!}{(7 - 0)! 0!} {(x)}^{7 - 0} \cdot {(3)}^{0} + \frac{7!}{(7 - 1)! 1!} {(x)}^{7 - 1} \cdot {(3)}^{1} + \dots + \frac{7!}{(7 - 7)! 7!} {(x)}^{7 - 7} \cdot {(3)}^{7}$

Simplify the exponents for each term of the expansion.

$1 \cdot {(x)}^{7} \cdot {(3)}^{0} + 7 \cdot {(x)}^{6} \cdot {(3)}^{1} + \dots + 1 \cdot {(x)}^{0} \cdot {(3)}^{7}$

Simplify the polynomial result.

$x^{7} + 21 x^{6} + 189 x^{5} + 945 x^{4} + 2835 x^{3} + 5103 x^{2} + 5103 x + 2187$

Expand Using the Binomial Theorem (x+3)^7

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