Factor (1-x)+5c(1-x)

$(1 - x) + 5 c (1 - x)$

Step 1

Remove parentheses.

$1 - x + 5 c (1 - x)$

Step 2

Factor $- 1$ out of $1 - x + 5 c (1 - x)$ .

Reorder the expression.

Reorder $1$ and $- x$ .

$1 - x + 5 c (- x + 1)$

Move $1$ .

$- x + 5 c (- x + 1) + 1$

Reorder $- x$ and $5 c (- x + 1)$ .

$5 c (- x + 1) - x + 1$

Factor $- 1$ out of $5 c (- x + 1)$ .

$- (- 5 c (- x + 1)) - x + 1$

Factor $- 1$ out of $- x$ .

$- (- 5 c (- x + 1)) - (x) + 1$

Rewrite $1$ as $- 1 (- 1)$ .

$- (- 5 c (- x + 1)) - (x) - 1 (- 1)$

Factor $- 1$ out of $- (- 5 c (- x + 1)) - (x)$ .

$- (- 5 c (- x + 1) + x) - 1 (- 1)$

Factor $- 1$ out of $- (- 5 c (- x + 1) + x) - 1 (- 1)$ .

$- (- 5 c (- x + 1) + x - 1)$

Step 3

Apply the distributive property.

$- (- 5 c (- x) - 5 c \cdot 1 + x - 1)$

Step 4

Rewrite using the commutative property of multiplication.

$- (- 5 \cdot - 1 c x - 5 c \cdot 1 + x - 1)$

Step 5

Multiply $- 5$ by $1$ .

$- (- 5 \cdot - 1 c x - 5 c + x - 1)$

Step 6

Multiply $- 5$ by $- 1$ .

$- (5 c x - 5 c + x - 1)$

Step 7

Factor.

Rewrite $5 c x - 5 c + x - 1$ in a factored form.

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$- ((5 c x - 5 c) + x - 1)$

Factor out the greatest common factor (GCF) from each group.

$- (5 c (x - 1) + 1 (x - 1))$

Factor the polynomial by factoring out the greatest common factor, $x - 1$ .

$- ((x - 1) (5 c + 1))$

Remove unnecessary parentheses.

$- (x - 1) (5 c + 1)$

Factor (1-x)+5c(1-x)

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