Factor 10x^2-23x+12

$10 x^{2} - 23 x + 12$

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 10 \cdot 12 = 120$ and whose sum is $b = - 23$ .

Factor $- 23$ out of $- 23 x$ .

$10 x^{2} - 23 (x) + 12$

Rewrite $- 23$ as $- 8$ plus $- 15$

$10 x^{2} + (- 8 - 15) x + 12$

Apply the distributive property.

$10 x^{2} - 8 x - 15 x + 12$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(10 x^{2} - 8 x) - 15 x + 12$

Factor out the greatest common factor (GCF) from each group.

$2 x (5 x - 4) - 3 (5 x - 4)$

Factor the polynomial by factoring out the greatest common factor, $5 x - 4$ .

$(5 x - 4) (2 x - 3)$

Factor 10x^2-23x+12

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