Factor 10x^2+23x+12

$10 x^{2} + 23 x + 12$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 10 \cdot 12 = 120$ and whose sum is $b = 23$ .

Factor $23$ out of $23 x$ .

$10 x^{2} + 23 (x) + 12$

Rewrite $23$ as $8$ plus $15$

$10 x^{2} + (8 + 15) x + 12$

Apply the distributive property.

$10 x^{2} + 8 x + 15 x + 12$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(10 x^{2} + 8 x) + 15 x + 12$

Factor out the greatest common factor (GCF) from each group.

$2 x (5 x + 4) + 3 (5 x + 4)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $5 x + 4$ .

$(5 x + 4) (2 x + 3)$

Factor 10x^2+23x+12

Related Questions

Support LCMGCF.com by disabling your adblocker.