Factor 125-8y^3

$125 - 8 y^{3}$

Step 1

Rewrite $125$ as $5^{3}$ .

$5^{3} - 8 y^{3}$

Step 2

Rewrite $8 y^{3}$ as ${(2 y)}^{3}$ .

$5^{3} - {(2 y)}^{3}$

Step 3

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 5$ and $b = 2 y$ .

$(5 - (2 y)) (5^{2} + 5 (2 y) + {(2 y)}^{2})$

Step 4

Simplify.

Multiply $2$ by $- 1$ .

$(5 - 2 y) (5^{2} + 5 (2 y) + {(2 y)}^{2})$

Raise $5$ to the power of $2$ .

$(5 - 2 y) (25 + 5 (2 y) + {(2 y)}^{2})$

Multiply $2$ by $5$ .

$(5 - 2 y) (25 + 10 y + {(2 y)}^{2})$

Apply the product rule to $2 y$ .

$(5 - 2 y) (25 + 10 y + 2^{2} y^{2})$

Raise $2$ to the power of $2$ .

$(5 - 2 y) (25 + 10 y + 4 y^{2})$

Factor 125-8y^3

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