Factor 16b^2+24b+9

$16 b^{2} + 24 b + 9$

Step 1

Rewrite $16 b^{2}$ as ${(4 b)}^{2}$ .

${(4 b)}^{2} + 24 b + 9$

Step 2

Rewrite $9$ as $3^{2}$ .

${(4 b)}^{2} + 24 b + 3^{2}$

Step 3

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$24 b = 2 \cdot (4 b) \cdot 3$

Step 4

Rewrite the polynomial.

${(4 b)}^{2} + 2 \cdot (4 b) \cdot 3 + 3^{2}$

Step 5

Factor using the perfect square trinomial rule $a^{2} + 2 a b + b^{2} = {(a + b)}^{2}$ , where $a = 4 b$ and $b = 3$ .

${(4 b + 3)}^{2}$